3.17 \(\int \frac {\cosh ^{-1}(a x)^2}{x} \, dx\)

Optimal. Leaf size=62 \[ \cosh ^{-1}(a x) \text {Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{2} \text {Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (e^{2 \cosh ^{-1}(a x)}+1\right ) \]

[Out]

-1/3*arccosh(a*x)^3+arccosh(a*x)^2*ln(1+(a*x+(a*x-1)^(1/2)*(a*x+1)^(1/2))^2)+arccosh(a*x)*polylog(2,-(a*x+(a*x
-1)^(1/2)*(a*x+1)^(1/2))^2)-1/2*polylog(3,-(a*x+(a*x-1)^(1/2)*(a*x+1)^(1/2))^2)

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Rubi [A]  time = 0.09, antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {5660, 3718, 2190, 2531, 2282, 6589} \[ \cosh ^{-1}(a x) \text {PolyLog}\left (2,-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{2} \text {PolyLog}\left (3,-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (e^{2 \cosh ^{-1}(a x)}+1\right ) \]

Antiderivative was successfully verified.

[In]

Int[ArcCosh[a*x]^2/x,x]

[Out]

-ArcCosh[a*x]^3/3 + ArcCosh[a*x]^2*Log[1 + E^(2*ArcCosh[a*x])] + ArcCosh[a*x]*PolyLog[2, -E^(2*ArcCosh[a*x])]
- PolyLog[3, -E^(2*ArcCosh[a*x])]/2

Rule 2190

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m*Log[1 + (b*(F^(g*(e + f*x)))^n)/a])/(b*f*g*n*Log[F]), x]
- Dist[(d*m)/(b*f*g*n*Log[F]), Int[(c + d*x)^(m - 1)*Log[1 + (b*(F^(g*(e + f*x)))^n)/a], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2282

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 2531

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> -Simp[((
f + g*x)^m*PolyLog[2, -(e*(F^(c*(a + b*x)))^n)])/(b*c*n*Log[F]), x] + Dist[(g*m)/(b*c*n*Log[F]), Int[(f + g*x)
^(m - 1)*PolyLog[2, -(e*(F^(c*(a + b*x)))^n)], x], x] /; FreeQ[{F, a, b, c, e, f, g, n}, x] && GtQ[m, 0]

Rule 3718

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (Complex[0, fz_])*(f_.)*(x_)], x_Symbol] :> -Simp[(I*(c + d*x)^(m +
1))/(d*(m + 1)), x] + Dist[2*I, Int[((c + d*x)^m*E^(2*(-(I*e) + f*fz*x)))/(1 + E^(2*(-(I*e) + f*fz*x))), x],
x] /; FreeQ[{c, d, e, f, fz}, x] && IGtQ[m, 0]

Rule 5660

Int[((a_.) + ArcCosh[(c_.)*(x_)]*(b_.))^(n_.)/(x_), x_Symbol] :> Subst[Int[(a + b*x)^n/Coth[x], x], x, ArcCosh
[c*x]] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0]

Rule 6589

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {\cosh ^{-1}(a x)^2}{x} \, dx &=\operatorname {Subst}\left (\int x^2 \tanh (x) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac {1}{3} \cosh ^{-1}(a x)^3+2 \operatorname {Subst}\left (\int \frac {e^{2 x} x^2}{1+e^{2 x}} \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )-2 \operatorname {Subst}\left (\int x \log \left (1+e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+\cosh ^{-1}(a x) \text {Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-\operatorname {Subst}\left (\int \text {Li}_2\left (-e^{2 x}\right ) \, dx,x,\cosh ^{-1}(a x)\right )\\ &=-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+\cosh ^{-1}(a x) \text {Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{2} \operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{2 \cosh ^{-1}(a x)}\right )\\ &=-\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (1+e^{2 \cosh ^{-1}(a x)}\right )+\cosh ^{-1}(a x) \text {Li}_2\left (-e^{2 \cosh ^{-1}(a x)}\right )-\frac {1}{2} \text {Li}_3\left (-e^{2 \cosh ^{-1}(a x)}\right )\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 63, normalized size = 1.02 \[ -\cosh ^{-1}(a x) \text {Li}_2\left (-e^{-2 \cosh ^{-1}(a x)}\right )-\frac {1}{2} \text {Li}_3\left (-e^{-2 \cosh ^{-1}(a x)}\right )+\frac {1}{3} \cosh ^{-1}(a x)^3+\cosh ^{-1}(a x)^2 \log \left (e^{-2 \cosh ^{-1}(a x)}+1\right ) \]

Warning: Unable to verify antiderivative.

[In]

Integrate[ArcCosh[a*x]^2/x,x]

[Out]

ArcCosh[a*x]^3/3 + ArcCosh[a*x]^2*Log[1 + E^(-2*ArcCosh[a*x])] - ArcCosh[a*x]*PolyLog[2, -E^(-2*ArcCosh[a*x])]
- PolyLog[3, -E^(-2*ArcCosh[a*x])]/2

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fricas [F]  time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\operatorname {arcosh}\left (a x\right )^{2}}{x}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccosh(a*x)^2/x,x, algorithm="fricas")

[Out]

integral(arccosh(a*x)^2/x, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {arcosh}\left (a x\right )^{2}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccosh(a*x)^2/x,x, algorithm="giac")

[Out]

integrate(arccosh(a*x)^2/x, x)

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maple [A]  time = 0.06, size = 98, normalized size = 1.58 \[ -\frac {\mathrm {arccosh}\left (a x \right )^{3}}{3}+\mathrm {arccosh}\left (a x \right )^{2} \ln \left (1+\left (a x +\sqrt {a x -1}\, \sqrt {a x +1}\right )^{2}\right )+\mathrm {arccosh}\left (a x \right ) \polylog \left (2, -\left (a x +\sqrt {a x -1}\, \sqrt {a x +1}\right )^{2}\right )-\frac {\polylog \left (3, -\left (a x +\sqrt {a x -1}\, \sqrt {a x +1}\right )^{2}\right )}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arccosh(a*x)^2/x,x)

[Out]

-1/3*arccosh(a*x)^3+arccosh(a*x)^2*ln(1+(a*x+(a*x-1)^(1/2)*(a*x+1)^(1/2))^2)+arccosh(a*x)*polylog(2,-(a*x+(a*x
-1)^(1/2)*(a*x+1)^(1/2))^2)-1/2*polylog(3,-(a*x+(a*x-1)^(1/2)*(a*x+1)^(1/2))^2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {arcosh}\left (a x\right )^{2}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arccosh(a*x)^2/x,x, algorithm="maxima")

[Out]

integrate(arccosh(a*x)^2/x, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {{\mathrm {acosh}\left (a\,x\right )}^2}{x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(acosh(a*x)^2/x,x)

[Out]

int(acosh(a*x)^2/x, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {acosh}^{2}{\left (a x \right )}}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(acosh(a*x)**2/x,x)

[Out]

Integral(acosh(a*x)**2/x, x)

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